If a ball is thrown into the air with a velocity of 12 m/s, its height (in meters) after t seconds is given by y = 12t − 4.9t2. Find the velocity when t = 1.

Answer 1

dy/dt = 12 - 9.8 t = 2.2 m/s

Answer 2

y = 12*1-4.9*1^2 = 12-4.9 = 7.1 m.