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Show that the points A(2,2), B(4,6) and C(10,-2) are the vertices of a right-angled triangle.
Answers
Answered by
oobleck
Check the lengths of the sides
AB = √((4-2)^2 + (6-2)^2) = √(4+16) = √20
Now do the others and check that a^2 + b^2 = c^2
where c is the longest side.
AB = √((4-2)^2 + (6-2)^2) = √(4+16) = √20
Now do the others and check that a^2 + b^2 = c^2
where c is the longest side.
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