Asked by Micheal
Hi can someone solve this for me.2logy = log2 + 3logx, 2 ^ y = 4 ^ x
Answers
Answered by
R_scott
taking antilog ... y^2 = 2 x^3
2^y = (2^2)^x ... 2^y = 2^(2x) ... y = 2 x
substituting ... 4 x^2 = 2 x^3
... solve for x , then substitute back to find y
2^y = (2^2)^x ... 2^y = 2^(2x) ... y = 2 x
substituting ... 4 x^2 = 2 x^3
... solve for x , then substitute back to find y
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