y = Yolanda's Age
d = Daughter's Age
y = 3d - 4
y + d > 88
y + d = 3d - 4 + d = 88
4d - 4 = 88
4d - 4 = 88
Yolanda is 4 years younger than 3 times her daughter's age. The sum of their ages is greater than 88.
What is the youngest age Yolanda's daughter can be?
2 answers
Daughter=x
Yolanda=3x-4
X+3x-4>88
X>88
Yolanda=3x-4
X+3x-4>88
X>88