Asked by annie

Solve this trig function over the interval [0, 2π)

2sin2(θ)−3sin(θ)+1=0
Answered by Yumeko
θ=5π/6,π/6,π/2
Answered by oobleck
(2sinθ-1)(sinθ-1) = 0
to get the answers given by Yumeko
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