Asked by Tyler

Two watches are set at 4:00 A.M. One watch is 2 min fast each hour. The second watch is 1 min late each hour. The faster watch will be one hour ahead of the slower watch at ____ A.M the next morning. I have no clue how to do this problem so please give me some hints. Thanks!
Answered by HMMMMM
5 Am

After the first hour the two watches will be three minutes apart and three minutes more. 60/3 which is after 20 hr, and since it is an hour and 3 apart you would have to do 9pm + 8 hr= 5Am
Answered by Tyler
Thank you so much!
Answered by HMMMMM
Your welcome!!
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