Question

A diver dives off a 32-meter high diving board into
the water below. If the diver pushes off with an initial
horizontal velocity of 1.2 m/s, how far from the base
of the board does she land?

Answer 1

vertically ... d = 1/2 g t^2 ... t = √(2 d / g)
... solve for t (time of flight)

horizontally ... d = v t = 1.2 * t