Question
Optimization Problem:
There is 300 square feet to construct an open top box with a square base. What dimensions are needed to maximize the volume, and prove that you have found the maximum
There is 300 square feet to construct an open top box with a square base. What dimensions are needed to maximize the volume, and prove that you have found the maximum
Answers
oobleck
x^2 + 4xh = 300
v = x^2 h = x^2 (300-x^2)/4x
dv/dx = 5/4 x^2 (180-x)
max v is where dv/dx = 0, at x=√180
v = x^2 h = x^2 (300-x^2)/4x
dv/dx = 5/4 x^2 (180-x)
max v is where dv/dx = 0, at x=√180