Asked by ryan
Having trouble with this question anyone know how to go about answering it?
Volume of a cylinder is increasing at a rate of 53π cm^3/sec, while the radius is increasing by 3 cm/sec. How fast is the height of the cylinder changing when its radius is 2 cm and the height is 3
cm?
Volume of a cylinder is increasing at a rate of 53π cm^3/sec, while the radius is increasing by 3 cm/sec. How fast is the height of the cylinder changing when its radius is 2 cm and the height is 3
cm?
Answers
Answered by
oobleck
v = πr^2 h
using the product rule,
dv/dt = 2πrh dr/dt + πr^2 dh/dt
Now plug in your numbers to find dh/dt
using the product rule,
dv/dt = 2πrh dr/dt + πr^2 dh/dt
Now plug in your numbers to find dh/dt
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