Asked by R L
What is limx->0 ((e^2x)-1)/(tanx)
Answers
Answered by
oobleck
Use l'Hôpital's Rule
2e^(2x)/sec^2(x) → 2e^0/1 = 2
2e^(2x)/sec^2(x) → 2e^0/1 = 2
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