What is limx->0 ((e^2x)-1)/(tanx)

limx→4 4x^2−15x−4/x−4.

limx¨0 sin ^3 (3x)/ x sin(x ^2)

limx->0 (3^x-6^x)/x please help here do not really know where to even start

if limx-->0(4-g(x)/x=1find limx--->0g(x)

limx-->3 sin 3x/4x

limx--->3- 5/x-3 I think it is -inf but I don't know how to prove it

Find limx→∞ e^−x = 1/e So would the answer be 0?

If limx→af(x)=L , where L is a real number, which of the following must be true? A) f'(a) exists...

limx->infinity 1/(x^2+4x+5)

evaluate limx->c (x^4-c^4)/(x^2-c^3)

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