Asked by Austin Bob
The 4- inch radius of a circle is increasing at a rate of 2 inches per second. How fast is the area increasing?
Answers
Answered by
oobleck
A = πr^2
dA/dt = 2πr dr/dt
Now plug in your numbers
dA/dt = 2πr dr/dt
Now plug in your numbers
Answered by
John
So im plugging in 2pie(4)? If so wjat do I do with the 2 inches per second ?
Answered by
oobleck
c'mon, man. In the first place, its <u>pi</u>, not pie.
They told you the radius is changing at 2in/s ... that is dr/dt
dA/dt = 2πr dr/dt = 2π*4*2 = 16π in/s
They told you the radius is changing at 2in/s ... that is dr/dt
dA/dt = 2πr dr/dt = 2π*4*2 = 16π in/s
Answered by
John
lol sorry im hungry. Thank you.
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