Asked by John paul
A single lane street 10 ft wide goes through a semicircular tunnel at the edge of each lane? Round off 2 decimal places
Answers
Answered by
Bosnian
You did not write the radius of the tunnel.
The equation of circle in the tunnel is:
x² + y² = r²
y = the height of the tunnel
r = the radius of the tunnel.
The intersection of the circle and x = 10 / 2 ft , x = 5 ft
x² + y² = r²
5² + y² = r²
25 + y² = r²
Subtract 25 to both sides
y² = r² - 25
y = √ ( r² - 25 )
and round on 2 decimal places
The equation of circle in the tunnel is:
x² + y² = r²
y = the height of the tunnel
r = the radius of the tunnel.
The intersection of the circle and x = 10 / 2 ft , x = 5 ft
x² + y² = r²
5² + y² = r²
25 + y² = r²
Subtract 25 to both sides
y² = r² - 25
y = √ ( r² - 25 )
and round on 2 decimal places
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