Asked by Drecon
A child with a mass of 45 kg is on top of a slide that is 12 m long and inclined 30 degrees along the horizontal. (a) Find the potential energy of the child at the top of the slide. How fast is the child going at the bottom of the slide if (b) the slide is frictionless and (c) if the coefficient of kinetic friction is 0.30?
Answers
Answered by
henry2,
sin30 = h/12
h = 6 m.
a. PE = mgh = 45*9.8*6 = ____Joules.
b. h = Vo*T+0.5gT^2 = 6
0+4.9T^2 = 6
T =
h = 6 m.
a. PE = mgh = 45*9.8*6 = ____Joules.
b. h = Vo*T+0.5gT^2 = 6
0+4.9T^2 = 6
T =
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