Asked by John
simplify the question with the restriction
x^2+9y^2/x-3y + 6xy/3y-x
x^2+9y^2/x-3y + 6xy/3y-x
Answers
Answered by
oobleck
Assuming the usual carelessness with parentheses, we have
(x^2+9y^2)/(x-3y) + 6xy/(3y-x)
= (x^2-7xy+9y^2)/(x-3y)
= (x-3y)^2/(x-3y)
= x-3y
as long as x-3y ≠ 0
(x^2+9y^2)/(x-3y) + 6xy/(3y-x)
= (x^2-7xy+9y^2)/(x-3y)
= (x-3y)^2/(x-3y)
= x-3y
as long as x-3y ≠ 0
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