Asked by Gideon
The rate of change of the radius of a sphere is constant. The rate of change of the volume is? TIA
Answers
Answered by
oobleck
v = 4/3 πr^3
dv/dt = 4πr^2 dr/dt
You can see that dv/dt is just the surface area times the change in radius.
dv/dt = 4πr^2 dr/dt
You can see that dv/dt is just the surface area times the change in radius.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.