A car with an initial position of 75 m and an initial velocity of 5.0 m/s accelerates at an average rate of 4 m/s^2 for 2.0 s. What id the car's position after 2.0 s?

Answer 1

x = Xi + Vi t + (1/2) a t^2
x = 74 + 5 * 2 + (1/2) * 4 * 2^2