Asked by Anonymous

City A is 300km east of city B, city C is 200km on a bearing of 123° from city B. how far is city C from city A
Answered by jacob
442
Answered by henry2,
Given: BC = 200km[123o], BA = 300km[90o]. AC = ?
AC = 300km[90o]+200km[123o]
AC = (300*sin90+200*sin123)+(300*cos90+200*cos123)i
AC = 252-109i = 275kn[-67o] = 275km[-67o] = 275km[293o]CW.
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