Asked by Michelle
Determine whether the infinite sequence converges or diverges. If it converges, find the limit.
{(1)(3)(5)...(2n-1) / (2n)^n}
{(1)(3)(5)...(2n-1) / (2n)^n}
Answers
Answered by
oobleck
For n > 2, you have
1*3*5/6*6*6 < 3/6^2
1*3*5*7/8*8*8*8 < 3/8^2
and so on. The nth term is less than 3/(2n)^2 so it converges to 0
1*3*5/6*6*6 < 3/6^2
1*3*5*7/8*8*8*8 < 3/8^2
and so on. The nth term is less than 3/(2n)^2 so it converges to 0
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