Asked by Helen
Reduce the fraction with a condition
y^2-16/3y+12
y^2-16/3y+12
Answers
Answered by
oobleck
this is the same as
(y-4)(y+4) / 3(y+4) = (y-4)/3 if y ≠ -4
(y-4)(y+4) / 3(y+4) = (y-4)/3 if y ≠ -4
Answered by
Bosnian
OR
y² -16 y / 3 + 12 =
y² - 16 ∙ y / 3 + 108 / 9
( y² - 16 ∙ y / 3 + 64 / 9 ) + 44 / 9 =
[ y² - 2 ∙ y ∙ ( 8 / 3 ) + ( 8 / 3 )² ] + 44 / 9 =
( y - 8 / 3 )² + 44 / 9
y² -16 y / 3 + 12 = ( y - 8 / 3 )² + 44 / 9
y² -16 y / 3 + 12 =
y² - 16 ∙ y / 3 + 108 / 9
( y² - 16 ∙ y / 3 + 64 / 9 ) + 44 / 9 =
[ y² - 2 ∙ y ∙ ( 8 / 3 ) + ( 8 / 3 )² ] + 44 / 9 =
( y - 8 / 3 )² + 44 / 9
y² -16 y / 3 + 12 = ( y - 8 / 3 )² + 44 / 9
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