Asked by Anand

Let there be a sequence of integers a_1, a_2, a_3,.... For each a_i, multiply a_i written in base 10 by 5^100. Then, in the product, replace each digit with its remainder when divided by 2. Read this new number as if it’s in base 2, and convert it into base 10. This is a_(i+1). Prove that if a_1 is a positive integer less than 2^101, this sequence is periodic and has period 2^k for some k.


I experimented with lower exponents (2, 3, 4) since 100 is a large number. However, I couldn’t find anything that will help me. Any help please?

Answers

There are no human answers yet.
There are no AI answers yet. The ability to request AI answers is coming soon!

Related Questions