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Asked by Michael

Find the absolute extremes of the function 𝑓(π‘₯)=π‘₯√(π‘₯βˆ’π‘₯^2)(provide answers as exact values).
4 years ago

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Answered by oobleck
y = x√(x-x^2)
y' = x(3-4x)/(2√(x-x^2))

since y is defined only on the interval [0,1]
min is at (0,0) and (1,0)
max is at (3/4, 3√3/16)
4 years ago

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