Asked by Sunday

THE 4th and 7th term of a.p are 15 and 27 respectively.find (a)the 1st term (b) common difference

Answered by Anonymous
a + 3 d = 15
a + 6 d = 27
----------------- subtract
-3 d = - 12
d = 4
onward and upward
Answered by Sunday
The 4th and 7th term of a.p are 15 and 27 respectively. Find (a) the 1st term (b) common difference
Answered by Anonymous
Ah, I just told you how to do it.
Answered by Bosnian
In an Arithmetic Progression:

an = a1 + ( n - 1 ) d

where

a1 = the initial term

d = the common difference of successive members is d,

an = the nth term


In this case:

a4 = a1 + ( 4 - 1 ) d = 15

a1 + 3 d = 15


a7 = a1 + ( 7 - 1 ) d = 27

a1 + 6 d = 27

Now you must solve system:

a1 + 3 d = 15

a1 + 6 d = 27
___________

Try to solve it.

The solution is a1 = 3 , d = 4

Yours A.P.

3 , 7 , 11 , 15 ,19 , 23 , 27...



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