compare the graphs of the logarithmic functions f(x)=log7x and g(x)=log4x for what values of x is f=g f>g and f<g explain how you know

Answer 1

log(1) = 0 for any base
I assume in your functions that 4 and 7 are the bases.
Since 4^x < 7^x, log4x > log7x for x>1
log4x < log7x for x<1

recall that if y = log_b(x) then
dy/dx = 1/lnb * 1/x