Calculate the volume of a 0.225 M solution of potassium hydroxide,KOH,required to react with 0.215g of acetic acid,CH,COOH=KCH,COO+H2O.

Answer 1

CH3COOH + KOH ==> CH3COOK + H2O
mols CH3COOH = grams/molar mass = 0.215/60 = about 0.0036 but that's just an estimate. You should recalculate everything.
mols KOH = the same since the mole ratio in the equation is 1 mol acetic acid to 1 mol KOH.
Then M = mols/L. You know M and you know mols, substitute and solve for L. Post your work if you get stuck.

Answer 2

Solve q