Asked by Anonymous
Determine the diameter of a close cylindrical tank having a volume of 11.3 cubic meter that would give the smallest surface area
Answers
Answered by
oobleck
1/4 d^2 h = 11.3
h = 45.2/d^2
a = π/2 d^2 + πdh = π/2 d^2 + 45.2π/d
da/dd = πd - 45.2π/d^2
da/dd=0 at d=3.56
h = 45.2/d^2
a = π/2 d^2 + πdh = π/2 d^2 + 45.2π/d
da/dd = πd - 45.2π/d^2
da/dd=0 at d=3.56
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