Asked by Anonymous
Determine the diameter of a close cylindrical tank having a volume of 11.3 cubic meter that would give the smallest surface area
Answers
Answered by
oobleck
1/4 d^2 h = 11.3
h = 45.2/d^2
a = π/2 d^2 + πdh = π/2 d^2 + 45.2π/d
da/dd = πd - 45.2π/d^2
da/dd=0 at d=3.56
h = 45.2/d^2
a = π/2 d^2 + πdh = π/2 d^2 + 45.2π/d
da/dd = πd - 45.2π/d^2
da/dd=0 at d=3.56
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.