plug in your points. If y=ax^2+bx+c, then
4a-2b+c = 9
16a-4b+c = 5
a+b+c = 0
Now just solve the system as usual
How can I locate an equation of the parabola in standard form passing through the points: (-2, 9), (-4, 5), (1, 0)
I am confused on how to do this one and I think some steps to find the answer would be helpful.
Thanks!
1 answer