Question

If 150 mL of 1.73 M aqueous NaI and 235 g of Pb(NO3)2 are reacted stoichiometrically according to the balanced equation, how many grams of Pb(NO3)2 remain?

Pb(NO3)2(aq) + 2NaI(aq) → PbI2(s) + 2NaNO3(aq)

Molar Mass (g/mol)
NaI 149.89
Pb(NO3)2 331.21
Density (g/mL)
-
Molar Volume (L)
22.4 at STP
Gas Constant
(L.atm.mol-1.K-1)
0.0821


show steps please

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