Asked by Emma
A man pushes a chair across the floor by applying a force of 155N at an angle of 25-degrees South of East. The chair accelerates to the right along the floor at 1.20 m/s.
So far I got this
Fg = mg (m)(9.81) = ?
Fa = 155 N 25 Degrees S of E
Fax = 155cos(25) = 140.777 N
Fay = 155sin(25) = 65.50 N
a = 1.20 m/s/s
FN = ?
Fk = μFN = ?
μ = ?
Fnet = ma
How do I find FN? Is it the same as Fg? or Is it the same as Fay?
So far I got this
Fg = mg (m)(9.81) = ?
Fa = 155 N 25 Degrees S of E
Fax = 155cos(25) = 140.777 N
Fay = 155sin(25) = 65.50 N
a = 1.20 m/s/s
FN = ?
Fk = μFN = ?
μ = ?
Fnet = ma
How do I find FN? Is it the same as Fg? or Is it the same as Fay?
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