Asked by Vanessa
Balance the following chemical equation using the oxidation number method:
K2Cr2O7 + SnCl2 + HCl → CrCl3 + SnCl4 + H2O + KCl
K2Cr2O7 + SnCl2 + HCl → CrCl3 + SnCl4 + H2O + KCl
Answers
Answered by
bobpursley
K +1 ; +1
Cr +6 ; +3 gained 3 electrons
Sn +2 ; +4 lost 2 electrons
Cl -1; -1
so the ratio of Cr to Sn is 2:3 so start out with these coefficents
K2Cr2O7 and 3SnCl2
That should get you there pretty quickly.
Cr +6 ; +3 gained 3 electrons
Sn +2 ; +4 lost 2 electrons
Cl -1; -1
so the ratio of Cr to Sn is 2:3 so start out with these coefficents
K2Cr2O7 and 3SnCl2
That should get you there pretty quickly.
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