I2 + 6H2O ==> 2IO3^- + 10e + 12H^+
[ClO3]^- + 6e + 6H^+ ==> Cl^- + 3H2O
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Make the electrons equal by multiplying eqn 1 by 3 and eqn 2 by 5 then add the two equations together. Finally adjust the species that appear on BOTH sides of the equations. 30 electrons, for example will appear on both side and there will be H2O on both sides as well as H^+ on both sides.
Balance the following chemical equation using the half reaction method in acidic conditions:
I2 + ClO3- → IO3- + Cl-
1 answer
1 answer