(a) f(-2) = 23 and f(-1) = -2
Since f(x) is continuous, there is no way to get from f(x) = 23 to f(x) = -2 without having f(x)=0 somewhere in the interval [-2,-1]
Now do the others in like wise
To confirm your answers graph the function and see where it crosses the x-axis.
given the function f(x)= x^4 -3x^3 -2x^2 + 5x + 1 use the intermediate value theorem to decide which of the following intervals contains at least one zero, select all that apply (4 answers)
a) [-2,-1]
b) [-1,0]
c) [0,1]
d) [1,2]
e) [2,3]
f) [3,4]
2 answers
The answers are:
a) [-2, -1]
b) [-1, 0]
d) [1, 2]
f) [3, 4]
If you put the equation on a graph, just look at where the line crosses the x-axis and what numbers it's between when it crosses. Hope this helps! :)
a) [-2, -1]
b) [-1, 0]
d) [1, 2]
f) [3, 4]
If you put the equation on a graph, just look at where the line crosses the x-axis and what numbers it's between when it crosses. Hope this helps! :)