The diameter of jupiter is approximately 9 × 10^4 miles. The diameter of earth is approximately 8 × 10^3 miles. Approximately how many times the diameter of earth is the diameter of jupiter

A.0.09
B.11
C. 0.9
D.110

User Icon for bobpursley bobpursley answered
3 years ago

what is 9e4/8e3 ? about 11

User Icon for Ashley Ashley answered
3 years ago

Hey people, PLEASE GIVE ME THE ANSWERS TO THE: Lesson 13: Patterns and Variables Unit Test CE 2015

Math 6 A Unit 4: Patterns and Variables PLEASE!!!!

User Icon for Jylan Jylan answered
3 years ago

A and/or B

User Icon for mark zuckerburg mark zuckerburg answered
3 years ago

0.09

User Icon for Clown Bot Clown Bot answered
1 year ago

Well, isn't Jupiter a big shot in the galaxy? Let me do some math while juggling these numbers!

So, if the diameter of Jupiter is approximately 9 × 10^4 miles and the diameter of Earth is approximately 8 × 10^3 miles, let's divide them and see how many Earths we can fit into Jupiter.

9 × 10^4 miles divided by 8 × 10^3 miles equals 11.25.

But hey, we can't have a fraction of an Earth, can we? So let's round that down to a whole number.

The answer is B. 11. Jupiter's diameter is approximately 11 times the diameter of Earth. That's one giant leap for Jupiter!

User Icon for Explain Bot Explain Bot answered
11 months ago

To find out how many times the diameter of Jupiter is the diameter of Earth, we divide the diameter of Jupiter by the diameter of Earth.

First, let's write the diameters of Jupiter and Earth in scientific notation:
Diameter of Jupiter = 9 × 10^4 miles
Diameter of Earth = 8 × 10^3 miles

To divide the diameter of Jupiter by the diameter of Earth, we divide the coefficients (9 and 8) and subtract the exponents (4 and 3).

9 ÷ 8 = 1.125
10^4 ÷ 10^3 = 10^(4-3) = 10^1 = 10

So, the diameter of Jupiter is approximately 1.125 × 10^10 times the diameter of Earth.

Now, let's convert this into a non-scientific notation.

1.125 × 10^10 can be written as 11,250,000,000.

The diameter of Jupiter is approximately 11,250,000,000 times the diameter of Earth.

Therefore, the answer is D. 110