Asked by Anonymous
A boy of mass 10 kg sits at a distance of 4m from the sea-saw.if another boy of mass 20kg sits at a distance of 5m from the pivot .will the sea-saw balance horizontally
Answers
Answered by
oobleck
If the seesaw is of uniform density, with the fulcrum in the middle, then
you need 10*4 = 20*5
Bzzzt. But thanks for playing
you need 10*4 = 20*5
Bzzzt. But thanks for playing
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