Question

A boy of mass 10 kg sits at a distance of 4m from the sea-saw.if another boy of mass 20kg sits at a distance of 5m from the pivot .will the sea-saw balance horizontally

Answer 1

If the seesaw is of uniform density, with the fulcrum in the middle, then
you need 10*4 = 20*5
Bzzzt. But thanks for playing