(11x^3 + ax^2 - x + b)-(4x^3 - 3ax + 5) = 7x^3 + ax^2 - (3a+1)x + (b+5)
That means
c = 7
a = 2
d = -(3a+1) = -7
b+5 = -1, so b = -6
When 4x^3 - 3ax + 5 is subtracted from 11x^3 + ax^2 - x + b, the result is cx^3 - 2x^2 + dx - 1.
How do you find a, b, c, and d?
1 answer
1 answer