The lines in the visible portion of the hydrogen spectrum are called the Balmer series, for which m=2 in the Rydberg equation. Calculate the wavelength in nanometers of the spectral line in this series for which n=4.

Answer 1

delta E = 2.180E-18 J(1/a^2 - 1/b^2) where a = 2 and b= 4) so
dE = 2.180E-18 J (1/2^2 - 1/4^2)
Solve for dE. Then dE = hc/wavelength. h is Planck's constant, c is speed of light. Solve for wavelength (in meters) and convert to nanometers. Post your work if you get stuck.

Answer 2

So for dE I got 4.0875 × 10-19 joules

Over

(6.62607004 × 10-34 m2 kg / s)(299 792 458 m / s)

Do I have to then covert into nm?