Looking at the mass relationships
8SO2>>8*64=512
16H2S=544 check those.
so now is to figure out how much of each divides the 93grams
SO2: 512/(1056)=.49*93=45.6 grams
H2S: the rest or 54.2 grams
Now how much S is that: 45.6*32/64=22.8 grams
plus 54.2*32/34=51.0 grams
add those (total S)=73.8 grams
check my calxulations
What is the maximum mass of S8 that can be produced by combining 93.0 grams of each reactant?
8SO2 + 16H2S ——> 3S8+16H2O
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