Asked by Usman Bilal
The overall balanced equation for the production of ethanol from glucose is as follow
C6H12O6 = 2C2H5OH + 2CO2
a) what is the theoratical yield of ethanol available from 10gram of glucose?
b) If in a particular experiment, 1gram of glucose produce 0.664gram of ethanol,what is the percentage yield?
C6H12O6 = 2C2H5OH + 2CO2
a) what is the theoratical yield of ethanol available from 10gram of glucose?
b) If in a particular experiment, 1gram of glucose produce 0.664gram of ethanol,what is the percentage yield?
Answers
Answered by
DrBob222
C6H12O6 = 2C2H5OH + 2CO2
How many moles in 10 g? That's mols = g/molar mass = 10/180 = 0.055
1 mol C6H12O6 produces 2 mols C2H5OH; therefore, 0.055 mols glucose will produce 0.11 mols ethanol. Then grams = mols x molar mass = 0.11 x 46 = approx 5.1 g C2H5OH.
b. If theoretical yield for 10 g is approximately 5.1 g then yield for 1 g would be approximately 0.51 g. Your experiment produced 0.664? That's over 100% yield. You should get a patent on this process. Can't be done.
How many moles in 10 g? That's mols = g/molar mass = 10/180 = 0.055
1 mol C6H12O6 produces 2 mols C2H5OH; therefore, 0.055 mols glucose will produce 0.11 mols ethanol. Then grams = mols x molar mass = 0.11 x 46 = approx 5.1 g C2H5OH.
b. If theoretical yield for 10 g is approximately 5.1 g then yield for 1 g would be approximately 0.51 g. Your experiment produced 0.664? That's over 100% yield. You should get a patent on this process. Can't be done.
There are no AI answers yet. The ability to request AI answers is coming soon!