Asked by mike
Using the balanced chemical equation and the initial mass of magnesium calculate the mass of hydrogen gas that should be produced when the reaction is complete
Balanced Chemical equation: Mg(s)+2HCI(aq)=MgCl_2+H_2Mg(s)+2HCI(aq)=MgCl2 +H2
Mass of Magnesium Metal
Trial 1: 0.089g
Trial 2: 0.179g
Balanced Chemical equation: Mg(s)+2HCI(aq)=MgCl_2+H_2Mg(s)+2HCI(aq)=MgCl2 +H2
Mass of Magnesium Metal
Trial 1: 0.089g
Trial 2: 0.179g
Answers
Answered by
oobleck
from the equation, each mole of Mg produces 1 mole of H2
So, figure how many moles of Mg you have, and multiply that by 2g to find the mass of H2.
So, figure how many moles of Mg you have, and multiply that by 2g to find the mass of H2.
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