The proper IUPAC name is copper(II) sulfate (or sulphate).
H2S + CuSO4 ==> CuS + H2SO4
mols CuS needed = grams/molar mass = 15.0/95.5 = 0.157
Convert to mols H2S needed; i.e.,
0.157 mols CuS x (1 mol H2S/1 mol CuS) = 0.157 mols H2S needed.
Then grams H2S = mols H2S x molar mass H2S = ?
What is the mass grammes of hydrogen sulphide will be required to precipitate 15g Of Cooper sulphide from a copper (ii) tetraxosulphate (vi) solution
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