X is partly constant and varies partly as y.when y=10,x=24and when y=14,x=36find x when y is 5

User Icon for oobleck oobleck answered
4 years ago

x = ay + b

so use the data given and you have
10a+b=24
14a+b = 36
subtract and you get
a=3, so b = -6
when y=5,
5*3 - 6 = 9

User Icon for Step-by-Step Bot Step-by-Step Bot answered
1 year ago

To find the value of x when y is 5, we need to determine the relationship between x and y.

Given that "X is partly constant and varies partly as y," we can assume that x has both a constant and variable component. Let's break down the information given:

When y = 10, x = 24.
When y = 14, x = 36.

From these values, we can see that the constant part of x is 24 and the variable part is 12 (36 - 24).

Now, we need to determine the relationship between the variable part of x (12) and the variable part of y as y changes from 10 to 14.

The change in y is (14 - 10) = 4, and the change in x is (36 - 24) = 12. Therefore, the rate of change between x and y is 12/4 = 3.

So, for every 1 unit increase in y, x increases by 3 units.

To find x when y is 5, we first need to determine the change in y from the given values:
Change in y = (10 - 5) = 5

Next, we calculate the corresponding change in x by multiplying the change in y by the rate of change:
Change in x = 5 * 3 = 15.

Lastly, we find the value of x when y is 5 by adding the change in x to the initial value of x (when y = 10):
x = 24 + 15 = 39.

Therefore, when y is 5, x is equal to 39.

User Icon for Explain Bot Explain Bot answered
11 months ago

To solve this problem, we can use the concept of direct variation. Direct variation is an equation of the form y = kx, where y and x are variables, and k is a constant.

In this case, we are given that x is partly constant and varies partly as y. This means that x can be expressed as the sum of a constant term and a variable term that is directly proportional to y. Mathematically, we can write it as:

x = c + ky

Given the values of x and y when y=10 (x=24) and y=14 (x=36), we can find the values of c and k by substituting these values into the equation.

When y = 10, x = 24:
24 = c + (10k) (equation 1)

When y = 14, x = 36:
36 = c + (14k) (equation 2)

Now we have a system of two linear equations. We can solve this system to find the values of c and k:

Subtracting equation 1 from equation 2:
36 - 24 = c + (14k) - (c + 10k)
12 = 4k

Dividing both sides by 4:
k = 3

Substituting the value of k into equation 1 to find c:
24 = c + (10 * 3)
24 = c + 30
c = -6

Now, we have the values of c and k.

Using the equation x = c + ky, we can find x when y is 5:
x = -6 + (3 * 5)
x = -6 + 15
x = 9

Therefore, when y is 5, x is 9.