Asked by mishel

A uniform metre rule of mass 120g is pivoted at the 60cm mark .at what pont on the meter rule should a mass of 50g be suspended for it to balance horizontal
Answered by mishel
l dont know
Answered by oobleck
the long side of the rule has 72g, the short side 48g
So, you need
72*30 = 48*20 + 50x
x = 24
so, the mass must be at the 84cm mark
Answered by Vero
84
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