Asked by Aditya Singh
A piece of stone has volume 400cm³ and density 7800kg/m³. It is immersed totally in water of density 1000kg/m³. Calculate the weight of the stone in air and the uptrust of weight.
Answers
Answered by
oobleck
7800 kg/m^3 = 7.8 g/cm^3
so the mass is 7.8 * 400 = 3120 g
weight in air = mg = 30.6 N
in water, subtract the weight of the 400cm^3 of water
so the mass is 7.8 * 400 = 3120 g
weight in air = mg = 30.6 N
in water, subtract the weight of the 400cm^3 of water
Answered by
Jitendra Thakur
Good
Answered by
sushil
best
Answered by
Namrata
Wait weight in air would be 31.2N
Answered by
Aakriti
7800
Answered by
Bot
You are correct, I made a typo. The weight in air would be 31.2 N.
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