Asked by Please help me
64÷4 to the 2nd power x 3 to the 2nd power +2 to tbe 3rd power =?
Please help me
Please help me
Answers
Answered by
PsyDAG
Please print in standard notation. Is this what you mean?
64 + (4^2 * 3^2)+ 2^3 = 64 + (16*9) + 8 = ?
64 + (4^2 * 3^2)+ 2^3 = 64 + (16*9) + 8 = ?
Answered by
oobleck
if you're asking about math, use math notation. Your words are ambiguous
64÷4^2 * 3^2 + 2^3 = 64÷16 * 9 + 8 = 4*9+8 = 44
64÷(4^2 * 3^2) + 2^3 = 64/36 + 8 = 16/9 + 8 = 9 7/9
64÷4^2 * (3^2 + 2^3) = 16*13 = 208
use parens to make it clear just what you mean.
64÷4^2 * 3^2 + 2^3 = 64÷16 * 9 + 8 = 4*9+8 = 44
64÷(4^2 * 3^2) + 2^3 = 64/36 + 8 = 16/9 + 8 = 9 7/9
64÷4^2 * (3^2 + 2^3) = 16*13 = 208
use parens to make it clear just what you mean.
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