Asked by jose
come on.
If k=1, than the values are
π/6 + 2π/3 = 5π/6
-π/6 + 2π/3 = π/2
5π/6 + 2π/3 = 3π/2
-5π/6 + 2π/3 = -π/6
So with k=1 you get the values π/2, -π/6
The next values will be those + or - 2π/3, so check to see which ones lie in the desired interval.
What am I adding 2pi/3 to? Will i have 4 answers?
If k=1, than the values are
π/6 + 2π/3 = 5π/6
-π/6 + 2π/3 = π/2
5π/6 + 2π/3 = 3π/2
-5π/6 + 2π/3 = -π/6
So with k=1 you get the values π/2, -π/6
The next values will be those + or - 2π/3, so check to see which ones lie in the desired interval.
What am I adding 2pi/3 to? Will i have 4 answers?
Answers
Answered by
Reiny
Is this in response to some sort of trig equation?
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.