Asked by jose

cos(3x)/cos(3x)+ sin(3x) + cos(3x)/cos(3x)-sin(3x) = 3

solve for x on pie/2 and -pie/2
Answered by oobleck
pi, NOT pie!
If you mean
cos(3x)/(cos(3x)+ sin(3x)) + cos(3x)/(cos(3x)-sin(3x)) = 3
then
cos(3x)(2cos(3x)) = 3(cos^2(3x)-sin^2(3x))
2cos^2(3x) = 6cos^2(3x) - 3
cos^2(3x) = 3/4
cos(3x) = ±√3/2
3x = ±π/6+2kπ/3, ±5π/6+2kπ/3
pick values of k that put x in [-π/2,π/2]
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