Asked by Anonymous

A girl of mass 48.0 kg is rescued from a building fire by leaping into a firefighters net. The window from which she leapt was 12.0 m above the net.She lands in the net so that she is brought to complete stop in 0.45 s.During this interval what is her change in momentum?

Answers

Answered by oobleck
mgh = 1/2 mv^2
So, v^2 = 9.81*12*2 = 235.44
her momentum upon impact was p = mv = 48 * 15.34 = 736.51 kg-m/s
So, ∆p = -736.51 kg-m/s
maybe you want the rate of change of p. In that case, just divide by 0.45s
Answered by Amjad Ali
It was very helpful
Answered by Zubair
Good
Answered by Anonymous
Solution is not right
Answered by Mishi
Good
Answered by Anonymous
Wrong solution . your answer is wrong
Answered by Aqsa Akram
I think its change in momentum as girl was leaping from height so the initial velocity is zero and final velocity simply can be derived from equation of motion.
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