A scuba diver dove from the surface of the ocean to an elevation of −59

Question

9/10
feet at a rate of −15 feet per minute. After spending 12 minutes at that elevation, the diver ascended to an elevation of −38
9/10
feet. The total time for the dive so far was 19
1/8 minutes. What was the rate of change in the diver's elevation during the ascent? Round your answer to the nearest hundredth.

Answer 1

rate of change = distance.time
time descending is 59.9/15 = 4 min
The diver rose 21 ft, so
21ft/(19 1/8 - 4 - 12) = 6.72 ft/min