solve exactly for a in the equation:
log a^5 + log a^(3/2) = log 625
4 2 8
the 4,2,8 are the bases
2 answers
log4 a^5 + log2 a^(3/2) = log8 625
let's convert to the same base 2
log4 a^5 = log2 a^5 /log2 4
= (1/2)(log2 a^5) since log2 4 = 2
similary log8 625
= log2 625/log2 8
so the new equation is
(1/2)(log2 a^5) + log2 a^(3/2) = (1/3)log2625
using the rules of logs
log2 a^(5/2) + log2 a^(3/2) = log2 625^(1/3)
log2 a^4 = log2 625^(1/3)
a^4 = 625^(1/3)
a = 5^(1/3) or the cuberoot of 5
log4 a^5 = log2 a^5 /log2 4
= (1/2)(log2 a^5) since log2 4 = 2
similary log8 625
= log2 625/log2 8
so the new equation is
(1/2)(log2 a^5) + log2 a^(3/2) = (1/3)log2625
using the rules of logs
log2 a^(5/2) + log2 a^(3/2) = log2 625^(1/3)
log2 a^4 = log2 625^(1/3)
a^4 = 625^(1/3)
a = 5^(1/3) or the cuberoot of 5