since gravity is an inverse square law,
multiplying the distance by 1/5, multiplies the force by a factor of (1/(1/5))^2 or 5^2
So the force changes to 25*5^2 = 625 N
Two objects attract each other with a gravitational force of 25 newtons from a given distance. If the distance between the two objects is reduced by a factor of 5, what is the changed force of attraction between them?
1 answer