Question

Solve radicals.
1. √8 /√32 (radical 8 divided by radical 32)
= √1/√4 (divided numerator & denominator by 4)
= 1/2 (simplify radical 1 over radical 4)

2. √7 /√49 (radical 7 divided by radical 49)
= √7 /7 (simplified radical 49 = 7, but kept radical 7 in numerator)
= √7/7 final answer (radical 7 over 7)

why wouldn't it be like 1st example:
√7 /√49
= √1/ 7 (divided both numerator and denominator by 7)
= 1 /7 (simplify radical 1 to be 1)

Answer 1

#1, correct
#2, your first answer is correct
"why wouldn' it be ....." ??
It is, but it would be the long way:
√7/√49 = √7/(√7*√7) = 1/√7 , not your √1/7 or 1/7
but 1/√7 = 1/√7 * (√7/√7)
= √7/7 , (since √x*√x = x )